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x^-6x^2+8x=0
We add all the numbers together, and all the variables
-6x^2+9x=0
a = -6; b = 9; c = 0;
Δ = b2-4ac
Δ = 92-4·(-6)·0
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{81}=9$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-9}{2*-6}=\frac{-18}{-12} =1+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+9}{2*-6}=\frac{0}{-12} =0 $
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